HACKER Q&A
📣 brudgers

Why do some electronics use 6.2 volts DC?


I don’t know very much about electronics.

I was poking around a new device and the power supply was supplying 6.18 volts to a board that appears to have 5v chips…the labels are rubbed off but one has “5v” written on it.

Then I looked in my box of wall warts and saw I have a 6.2 volt adapter. So I am curious why would an EE use 6.2 rather than 5 volts?

For context, the device is a tabla drum machine. The power supply is a bit janky. It uses line level AC. I would like to just power the board directly with a barrel plug and that seems within my ability.


  👤 tempest345 Accepted Answer ✓
Around 6.3V was a standard voltage for vacuum tube heater pins (the part that emitted free electrons via thermal emission inside the tube to be available for the electrical fields to accelerate).

My guess would be that historically 6.3V supplies made forvacumee tubes where commonly available when transistor based electronics where created so it made sense to utilize them. Works quite nicely for the typical 5V circuits as a "rough" input voltage to be feed through a LDO regulator, for example. And so it just stuck.


👤 hw-guy
Just a guess...maybe the 5V is supplied from a linear regulator with a maximum dropout of 1.2V, so the board is specified to require at least 6.2V from the wall wart.

👤 ofalkaed
Could also be simple pragmatics or the economy of scale. If your business makes both 5V and 6.2V devices it could be a decent cost saving to make them both use 6.2V adapters, unless production number are low burning off that extra 1.2V in the 5V devices will generally be cheaper than separate power adapters for each and if nothing else it is one less inventory item to deal with.

👤 ofalkaed
It could also be that some of the circuit needs a higher voltage, just because some parts are 5V does not mean they all are.

👤 lmpdev
Possibly a linear regulator (does the device get warmer than you'd expect?)

Although the LM7805 would need ~7V minimum

RE those chips: almost all general purpose components have a usable voltage range. From LEDs to MCUs, most components can tolerate a few hundred millivolts from its ideal V_{f}, some even dozens of volts - especially solid state stuff like CMOS ICs

The only time I really recommend not f*cking with aftermarket PSUs is if it's primarily charging or powering: - lithium batteries - super or ultra capacitors


👤 amelius
Battery voltages go in multiples of about 1.5V typically. Perhaps that could be the reason?

👤 schappim
It is mostly for voltage headroom/power dissipation along w/ the use of 6.2V Zener diodes(hear: voltage regulation). The use of 6.2V also gives you some margin for noise.

👤 Berniek
Well, 6.3V is an interesting value. The European standard voltage AC is 220V, many countries use 240V (or 230V) So we want 5V to power our whatever. Regulators need some overhead usually .6~1.2V so we need 6.2V as a minimum. BUT THAT IS DC. When you rectify AC (turn it into DC) you actually get PULSES of DC with peak of 1.414 time the AC value. To make it straight DC you need a capacitor. But as you draw current from the capacitor it can't charge up (it has a charge time constant caused by the impedance of the transformer and its capacitance) so you get ripple. The more current you take, the more ripple. So you put a regulator to keep the DC output below the ripple as much as you can. So now to do the maths. Using the SAME transformer on each of the supplies we get the peak output of 8.9V on 220V & 9.7V on 240V Now we need 5V so that gives us an overhead of 8.9-5 = 3.9V and 9.7-5=4.7V. That is plenty of overhead if we had DC but we have pulsed DC that is smoothed by a capacitor so as we draw current the capacitor can't stay charged fully so you end up with DC with ripple at the input to the regulator so that overhead needed by the regulator at the troughs of the ripple can be eroded. So you can drawer less current or give more initial overhead. The more overhead you start with the more heat the regulator has to deal with so you need it to operate with just the right amount of overhead. By the way the ripple component is like AC and its heating effects are actually reduced (the maths says its about .64 times the same value of DC). This is true for the non switching regulators, with those there is a new set of problems with the output ripple (which is usually very high frequency and easier to filter out even with small value capacitance). This may cause radio interference within the circuits but good design should eliminate that. The ideal overhead seems to be ~4V. The regulator power dissipation (it gets hot with bigger overhead) is a trade off. You can operate with less but you need a bigger transformer (to supply more charge current to the transformer or bigger capacitance and that means more cost). By the way so you have 110V or 120V AC. The 2 values are directly related to the 220 & 240V.

But why 6.3V? Well like a lot of traditional designs, the heater voltage of vacuum tubes was nominally 6.3V so the transformer design was already done. Also putting 6V battery with vacuum tubes is likely to shorten their life, (the DC equivalent of 6.3V used for heating is 4V), but the early batteries had a fairly high internal resistance so the voltage supplied to the heaters was usually much less.

A quick note is in order about values. Why pick individual values? History and experience tell us that certain values are efficient. Metric is very good for measuring distances, but not good for measuring bolts where the imperial system reigns supreme (a 1/2 inch long bolt has more useful applications than a 10 mil long bolt where a 15 mil bolt is too long). Same goes for fathoms. It is a much better measurement of depth because nearly all water bodies will have ripple or waves and waves of 6 feet make an error in depth of 1 in fathoms or an error of 6 in feet.

Turns out 6.3V seems to be efficient for both vacuum tubes and regulators!


👤 guerrilla
Definitely sounds like a linear regulator is in use.