HACKER Q&A
📣 martyalain

Is there a life out of closures?


Is there a life out of closures?


  👤 martyalain Accepted Answer ✓
Closures are not a required functionality in a language. I'm experimenting a homemade language, lambdatalk, http://lambdaway.free.fr/lambdawalks/ , in which lambdas don't create closures but accept partial application. For instance this is how the set [cons, car, cdr] could be defined in SCHEME:

  (def cons (lambda (x y) (lambda (m) (m x y))))
  (def car (lambda (z) (z (lambda (x y) x))))
  (def cdr (lambda (z) (z (lambda (x y) y))))

  (car (cons 12 34)) -> 12
  (cdr (cons 12 34)) -> 34
and in lambdatalk:

  {def cons {lambda {:x :y :m} {:m :x :y}}} 
  {def car {lambda {:z} {:z {lambda {:x :y} :x}}}}
  {def cdr {lambda {:z} {:z {lambda {:x :y} :y}}}}

  {car {cons 12 34}} -> 12
  {cdr {cons 12 34}} -> 34
In SCHEME the outer lambda saves x and y in a closure the inner lambda can access given m. In lambdatalk the lambda saves :x and :y and returns a new lambda waiting for :m. So, even if closure (and lexical scope) are usefull functionalities, there are not a necessity. Without any free variables, out of any lexical scope, functions are true black boxes without any side effect, in a total independance, following a true functional paradigm. Don't you think so?