What happens to things thrown into Schwarzschild radius of Earth?

Question

Suppose we have some kind of large and heavy object like the Earth, but without heat inside. The gravitational radius of the Earth is ~8.8 mm. We drilled a hole in the very center of this object, so we are absolutely sure that any ball thrown into the hole at some point is completely within this radius. What happens to the ball at this moment? Will it continue to fall by inertia? Will it be swallowed up by a black hole? Maybe there will be something else?

bell-cot · Accepted Answer

There is no black hole, and nothing special happens. The ball would keep moving due to inertia. (Acceleration due to gravity is ~zero near the center of any passably-symmetrical mass. Actually - unless your hole was air-tight and pumped down to a hard vacuum, the ball would ~never reach the center, due to air resistance.)

tlb · Answer

The Schwarzchild radius is only meaningful if all the mass is inside the radius. The calculation isn't valid in the interior of a larger object.In fact, the gravity near the center of a planet goes to zero, since the surrounding mass is warping spacetime equally in all directions.

raxxorraxor · Answer

8.8mm or 8.8Mm (milli or Mega)? Why these numbers? Anyway I would say that any inertia of the ball is irrelevant compared to the gravitational forces.
Assuming we had a magical drill, the drilled hole would immediately collapse due to gravity.
Assuming there would be a magic force preventing the collapse, the ball should stay in the center of the hole as there is net zero gravity right at the center. The inertia could let it overshoot a bit, but it would be pulled back as it possesses a negligible mass compared to the heavy object and therefore its inertia is quite small compared to the gravitational forces.

neximo64 · Answer

The ball would be ripped apart by tidal forces and fall into the radius.