HACKER Q&A
📣 acomagu

TS: Why isn't union type in object field extracted to out of the object?


I think these type should be equal:

  { a: string | undefined }
  { a: string } | { a: undefined }
These mean same set of values. And if these are equals, the following works:

  Exclude<{ a: string | undefined }, { a: string }>   // => { a: undefined }
But it don't work as I expected. Because { a: string | undefined } is not { a: string } | { a: undefined }.

If it works, Exclude could be considered as subtraction of set in mathematical context. I think there is big deals if these types are equals. Why not? And please tell me related GitHub issues if you know.


  👤 valand Accepted Answer ✓
Must be happening for a reason: - Type equivalence is an edge case not covered yet - Type equivalence calculation is too expensive so that compilation time is preferred than type equivalence completeness

If you would, please post it in issues, that'll be great https://github.com/microsoft/TypeScript/issues